Question

Sketch a graph of the quadratic function with the given vertex and through the given point. Then write the equation of the parabola in vertex form and describe how the function was transformed from the parent function y = x^2

vertex (0, 0), point (-2, 3)

Answer 1

The graph of the quadratic function is a parabola that opens up and has a vertex at (0, 0). It passes through the point (-2, 3). The graph is shown below.

The equation of the parabola in vertex form is y = (x - 0)^2 + 0. This equation was transformed from the parent function y = x^2 by shifting the graph to the right 0 units and up 0 units.

Answer 2

AAAaannndd the bot gets it wrong yet again!
if vertex is at (0,0) then y = ax^2
so 4a = 3, making y = 3/4 x^2
no shifting, just scaling by 3/4