AE = 4x + 20
BD = 3x + 5
Subtract BD from AE:
AE - BD = 4x + 20 - (3x + 5)
AE - BD = x + 15
Therefore, x = 15
B is the midsegment of AC and D is the midsegment of CE. Solve for x, given BD = 3x+5 and AE = 4x+20
2 answers
since we have no idea where E is, this is pretty much impossible