Question
Given two vectors A and B A=2i +j _3k and B=3i +2j+k .find A×B, B, a.b , c,the angle between a.b is
Answers
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A x B = (2j - 3k)i + (-3i + 2k)j + (2 - 2j)k
a.b = 2(3) + 1(2) + (-3)(1) = 7
c = |A| |B| = sqrt(13) sqrt(6) = sqrt(78)
The angle between A and B = cos-1(7/sqrt(78)) = 57.3°
a.b = 2(3) + 1(2) + (-3)(1) = 7
c = |A| |B| = sqrt(13) sqrt(6) = sqrt(78)
The angle between A and B = cos-1(7/sqrt(78)) = 57.3°