Asked by MIMI
what is the area of a trapazoid:
1/2*(12+5.4)*6
1/2*(12+5.4)*6
Answers
Answered by
GanonTEK
Area of Trapezoid = h*((a+b)/2)
where a and b are the two parallel sides and h is the perpendicular height.
If your a and b are 12 and 5.4 and the perpendicular height is 6 then your equation above is correct.
where a and b are the two parallel sides and h is the perpendicular height.
If your a and b are 12 and 5.4 and the perpendicular height is 6 then your equation above is correct.
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