find the area of triangle ABC if A=56 degrees, b=20 ft, and c=12 ft. Round to the nearest tenth.
2 answers
area of a triangle is 1/2 a*b*sinA, correct?
Area of a triangle = (1/2)bcSinA
Or in words, a half times the length of two sides times the Sin of the angle between those two lines.
So Area = (0.5)*(20)*(12)*Sin(56)
Area = 120*Sin(56)
Area = 99.48
And rounded to the nearest 10th [or to one decimal place in other words]
Area = 99.5 ft sq
I just put some extra information about the sides and angles below in case you were not 100% sure why angle A is between side b and c.
Angle A is opposite Side a
Angle B is opposite Side b
Angle C is opposite Side c
So
Angle A is between Sides b and c
Angle B is between Sides a and c
Angle C is between Sides a and b
Ok, hope that helps
Or in words, a half times the length of two sides times the Sin of the angle between those two lines.
So Area = (0.5)*(20)*(12)*Sin(56)
Area = 120*Sin(56)
Area = 99.48
And rounded to the nearest 10th [or to one decimal place in other words]
Area = 99.5 ft sq
I just put some extra information about the sides and angles below in case you were not 100% sure why angle A is between side b and c.
Angle A is opposite Side a
Angle B is opposite Side b
Angle C is opposite Side c
So
Angle A is between Sides b and c
Angle B is between Sides a and c
Angle C is between Sides a and b
Ok, hope that helps