Question

A disc of radius 2m and mass 100kg rolls on horizontal floor and it rolls continue 20s . how much energy has that body
The kinetic energy of the disc is given by the equation KE = 1/2 mv^2, where m is the mass of the disc and v is the velocity of the disc.

Assuming the disc is rolling at a constant velocity, the kinetic energy of the disc after 20 seconds is given by:

KE = 1/2 * 100kg * (2m/20s)^2 = 20 J

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