Question

f(x)=3-3x^2 -3 <= x <= 2

How do you find the absolute max and min value?
What does x equal?

Answer 1

Th max and the minimum value will occur where the derivative is zero, OR at one of the endpoints (2 or -3)

When the derivative is zero
df/dx = 0 = -6x
x = 0.

Since this is an upside-down parabola with a maximum value of 3 (at x=0), the minimum value will be where x = -3, which is as far as possible from x = 0

Answer 2

I don't understand how to get the min??

Answer 3

nevermind i got it! thanks!