If your equation is
C2H4 + 3O2 → 2CO2 + 2H2O
then you have
45g of C2H4 = 45/28 = 1.607 moles
The equation tells you that will require 3*1.607 = 4.821 moles of O2
How many moles of O₂ are required for the complete reaction of 45 g of C₂H4 to form CO₂
and H₂O?
1 answer