Asked by Oti
lim (x^2+linx)/(5x^2+x+1) as x approaches infinity
Answers
Answered by
oobleck
since lnx grows more slowly than x, the limit will be the same as for
x^2/(5x^2+x+1)
and the limit of that is just 1/5
not sure what linx is ...
x^2/(5x^2+x+1)
and the limit of that is just 1/5
not sure what linx is ...
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