Calculate the percentage of carbon in ethanedioic acid Crystal

C2H2O4.2H2O.

User Icon for DrBob222 DrBob222 answered
1 year ago

mm = molar mass

am = atomic mass
%C = (2*am C)*100/mm C2H2O4.2H2O
%H = (6*am H)*100/mm C2H2O4.2H2O
%O = (6*am O)*100/mm C2H2O4.2H2O
Check it to see that the total is 100%.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

To calculate the percentage of carbon in ethanedioic acid crystal (C2H2O4ยท2H2O), you need to determine the molar mass of carbon and the molar mass of the compound.

1. Calculate the molar mass of carbon (C):
The atomic mass of carbon is 12.01 g/mol.

2. Calculate the molar mass of the compound (C2H2O4ยท2H2O):
- Two carbon atoms: (2 * 12.01 g/mol) = 24.02 g/mol
- Two hydrogen atoms: (2 * 1.01 g/mol) = 2.02 g/mol
- Four oxygen atoms in the acid: (4 * 16.00 g/mol) = 64.00 g/mol
- Two water molecules: (2 * [(2 * 1.01 g/mol) + (1 * 16.00 g/mol)]) = 72.08 g/mol

Total molar mass of the compound = (24.02 g/mol) + (2.02 g/mol) + (64.00 g/mol) + (72.08 g/mol) = 162.12 g/mol

3. Calculate the percentage of carbon in the compound:
Carbon's contribution to the total molar mass = (24.02 g/mol) / (162.12 g/mol)

4. Convert the fraction to a percentage:
Percentage of carbon = (24.02 g/mol) / (162.12 g/mol) * 100

Therefore, the percentage of carbon in ethanedioic acid crystal is approximately 14.80%.