mm = molar mass
am = atomic mass
%C = (2*am C)*100/mm C2H2O4.2H2O
%H = (6*am H)*100/mm C2H2O4.2H2O
%O = (6*am O)*100/mm C2H2O4.2H2O
Check it to see that the total is 100%.
C2H2O4.2H2O.
am = atomic mass
%C = (2*am C)*100/mm C2H2O4.2H2O
%H = (6*am H)*100/mm C2H2O4.2H2O
%O = (6*am O)*100/mm C2H2O4.2H2O
Check it to see that the total is 100%.
1. Calculate the molar mass of carbon (C):
The atomic mass of carbon is 12.01 g/mol.
2. Calculate the molar mass of the compound (C2H2O4ยท2H2O):
- Two carbon atoms: (2 * 12.01 g/mol) = 24.02 g/mol
- Two hydrogen atoms: (2 * 1.01 g/mol) = 2.02 g/mol
- Four oxygen atoms in the acid: (4 * 16.00 g/mol) = 64.00 g/mol
- Two water molecules: (2 * [(2 * 1.01 g/mol) + (1 * 16.00 g/mol)]) = 72.08 g/mol
Total molar mass of the compound = (24.02 g/mol) + (2.02 g/mol) + (64.00 g/mol) + (72.08 g/mol) = 162.12 g/mol
3. Calculate the percentage of carbon in the compound:
Carbon's contribution to the total molar mass = (24.02 g/mol) / (162.12 g/mol)
4. Convert the fraction to a percentage:
Percentage of carbon = (24.02 g/mol) / (162.12 g/mol) * 100
Therefore, the percentage of carbon in ethanedioic acid crystal is approximately 14.80%.