Asked by Imani Kisonga
If a cup of coffee has temperature 95∘C in a room where the temperature is 20∘C, then, according to Newton's Law of Cooling, the temperature of the coffee after t minutes is
T(t)=20+75e^(−t/50).
What is the average temperature (in degrees Celsius) of the coffee during the first half hour?
Average temperature =
T(t)=20+75e^(−t/50).
What is the average temperature (in degrees Celsius) of the coffee during the first half hour?
Average temperature =
Answers
Answered by
oobleck
as usual, the average value over the 30-minute interval is
1/30 ∫[0,30] 20+75e^(−t/50) dt = 76,40
1/30 ∫[0,30] 20+75e^(−t/50) dt = 76,40
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.