Asked by Adrian
For the function F(t)=3^t, let f(t)=F′(t). Write the integral ∫^{b}_a f(t)dt and evaluate it with the Fundamental Theorem of Calculus.
∫^{3}_0 =
dt=
(Note that your answer must be exact, not a decimal approximation.)
∫^{3}_0 =
dt=
(Note that your answer must be exact, not a decimal approximation.)
Answers
Answered by
oobleck
∫[a,b] f(t) dt = F(b) - F(a) = 3^b - 3^a
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