Question

Br
|
CH3 - CH2 - CH - CH - CH2 -CH3
|
CH2CH3


How would I name the structure above? Would it be 3-bromo-3-methylpentane?

Answer 1

I meant 3-bromo-3-ethylpentane

The bromine and ethyl group are off the third (CH) not the first (CH3)

Answer 2

No. First, you have some serious problems with what you drew. I see a 6-valent carbon, and two 3-valent carbons.Don't get confused because the carbon turns the corner. The LONGEST chain is the way you want to go and the longest chain is 8 carbons assuming you just didn't add enough H atoms to the middle 3-valent Cs and you added too many Hs to the 6-valent C; therefore, it is an octane. I think everyone would know how to draw the structure from your name; however, it isn't correct. I would name it as 3-bromooctane (with those parameters I named above).

Answer 3

.............Br
.............|
CH3 - CH2 - CH - CH2 -CH3
.............|
..........CH2CH3

This is what I meant to draw. The Br and ethyl group just shifted over after I clicked post answer.

So would this be 3-bromo-3-ethylpentane

Answer 4

OK. I see what has happened. You tried to space it so the Br comes off the third C and the methyl group off the third C but you can't space on the boards, at least not easily. If you put both Br and ethyl groups on the same C atom, then that C atom has too many bonds (you need to take off a H atom) and the C to the right doesn't have enough H atoms). If the Br comes of carbon 4 and the ethyl off carbon 3, then the H atoms are attached correct. At any rate, I still count six C atoms in a line which makes it a hexane. Perhaps I just don't see how you intended to draw it. You can describe it; however, and we can go from there.

Answer 5

CH3 - CH2 - CH (which has a Br and ethyl group off of it) - CH2 - CH3

- so basically the Br and CH2CH3 shift over to the CH

Answer 6

Is that the structure you intended. One CH2 has the ethyl and Br on it which makes too many bonds and the carbon to the right has a CH. I'll bet that is where you want the Br and ethyl group?

Answer 7

yes that's where it would go then. Is the C making too many bonds because I count 5? Should I get rid of the hydrogen?

Answer 8

-------Br
-------|
CH3CH2-CH-CH2CH3
-------|
-------CH2CH3
Let me post this and see how it looks. I think this is what you have been trying to draw.

Answer 9

No, that's not it. Move the Br to the carbon on the right and move the ethyl group to the C on the right.
That will be 3-bromo-3-ethylpentane which I think is what you had at the beginning.