2PbCrO4 + HCl + 2FeSO4 ----> PbCl2 + Cr2 (SO4)3 + H2O + Fe2(SO4)3
In the above equation, I have adjusted two of the coefficients. Now, just go through and balanced the oxidation/reduction part. Keep the number of electrons equal.
Cr changes from +6 for each atom on the left to +3 for each atom on the right. Fe changes from +2 for each atom on the left to +3 for each atom on the right.
Okay, in this prolem i need to balence this equation. Even our teacher had problems with it, but he refuses to help anyone.
PbCrO4 + HCL + FeSO4 ----> PbCl2 + Cr2 (SO4)3 + H2O + Fe2(SO4)3
please help me. this is the last problem on my homework.
then im off to start math :)
Thank you!
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1 answer