Question

damon and bob I am not so bright. When I originally posted my question I mistakenly put an = sign where there should have been a + sign. the equation should read like this:

(x^2 - 2x)(x + 3) = -2x(x + 1)

What does this do to the solution now???

Answer 1

x^3 + 3 x^2 - 2 x^2 - 6 x + 2 x^2 + 2 x = 0
No change. Reiny guessed what you meant way back
x^3 + 3 x^2 - 4 x = 0
x(x^2 + 3 x - 4 ) = 0
x (x+4)(x-1) = 0
x = 0
x = -4
x = 1

Answer 2

Damon thanks for the help. I had the sign wrong. I am having trouble with the whole sign thing. I just submitted my test and I missed 4 of the multiple choice questions and each one was because I had the signs wrong. I had the correct numbers just the wrong signs.

Answer 3

Go very slowly then
x^3 + 3 x^2 - 2 x^2 - 6 x = - 2 x^2 - 2 x
then add the quantity + 2 x^2 + 2 x to both sides to make the right side zero.