Question
3cos2x-sinx=0
Answers
oobleck
assuming you want a solution, use your double-angle formula to get
3(1 - 2sin^2x)-sinx = 0
6sin^2x + sinx - 3 = 0
sinx = (-1±√73)/12 = -0.79533 or 0.62867
so now finish it off, placing your results in the desired quadrants.
3(1 - 2sin^2x)-sinx = 0
6sin^2x + sinx - 3 = 0
sinx = (-1±√73)/12 = -0.79533 or 0.62867
so now finish it off, placing your results in the desired quadrants.