Asked by Lawal R
3cos2x-sinx=0
Answers
Answered by
oobleck
assuming you want a solution, use your double-angle formula to get
3(1 - 2sin^2x)-sinx = 0
6sin^2x + sinx - 3 = 0
sinx = (-1±√73)/12 = -0.79533 or 0.62867
so now finish it off, placing your results in the desired quadrants.
3(1 - 2sin^2x)-sinx = 0
6sin^2x + sinx - 3 = 0
sinx = (-1±√73)/12 = -0.79533 or 0.62867
so now finish it off, placing your results in the desired quadrants.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.