Asked by Anonymous
Two fair six-sided dice are rolled.
What is the probability that the sum of the numbers rolled is either 6 or 12?
Responses
136+136=2361 over 36 plus 1 over 36 is equal to 2 over 36
536+112=295 over 36 plus 1 over 12 is equal to 2 ninths
16+136=7361 sixth plus 1 over 36 is equal to 7 over 36
536+136=16
What is the probability that the sum of the numbers rolled is either 6 or 12?
Responses
136+136=2361 over 36 plus 1 over 36 is equal to 2 over 36
536+112=295 over 36 plus 1 over 12 is equal to 2 ninths
16+136=7361 sixth plus 1 over 36 is equal to 7 over 36
536+136=16
Answers
Answered by
Bosnian
When two dice are rolled , 6 • 6 = 36 sums are possible.
There are five possible sums of 6:
( 1 , 5 ) , ( 2 , 4 ) , ( 3 , 3 ) , ( 4 , 2 ) , ( 5 , 1 )
It has one possible sum of 12:
( 6 , 6 )
Probability sum is 6 or 12 =
5 / 36 + 1 / 36 = 6 / 36 =
6 • 1 / 6 • 6 = 1 / 6
There are five possible sums of 6:
( 1 , 5 ) , ( 2 , 4 ) , ( 3 , 3 ) , ( 4 , 2 ) , ( 5 , 1 )
It has one possible sum of 12:
( 6 , 6 )
Probability sum is 6 or 12 =
5 / 36 + 1 / 36 = 6 / 36 =
6 • 1 / 6 • 6 = 1 / 6
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