Question

I have my solution to this problem but I am not very confident in it being correct. I just want to see if some one else comes up with the same answer.

Solve (x^2 - 2x)(x + 3) = -2x(x = 1)

Answer 1

I think you meant
(x^2 - 2x)(x + 3) = -2x(x + 1) since the = and + signs are on the same key

after expanding and simplifying I got
x^3 + 3x^2 - 4x = 0
x(x^2 + 3x - 4) = 0
x(x+4)(x-1) = 0
so x = -4,0,1

how does that compare with yours ?

Answer 2

Reiny how did you get to the -4x? I came up with -8x which does not allow for any more reduction.

Answer 3

x^3 + 3 x^2 -2 x^2 - 6 x + 2 x^2 + 2 x = 0
note that -6x + 2 x = -4x
x^3 + 3 x^2 -4 x = 0

x ( x^2 + 3 x - 4) = 0