Asked by Awolaja favour
A stone is shoot from a catapult with initial velocity of 30m/s of an elevation of 60° find the time of flight and maximum height attained and the range with working
Answers
Answered by
oobleck
the wikipedia article on Trajectory has this and much more.
since v = 30 sin60° - 9.8t, it takes 2*(30 sin60°)/9.8 seconds to land
h = v^2/2g sin^2 60°
R = v^2/g sin120°
since v = 30 sin60° - 9.8t, it takes 2*(30 sin60°)/9.8 seconds to land
h = v^2/2g sin^2 60°
R = v^2/g sin120°
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