Asked by Nelle
How can Ag2Cro4 have a four on the O? Ag has a charge of two, so multiplying it by 2 would give me two, but multiplying Cr, with a charge of two (one of its few choices) by four would give me eight. How does that balance? Thank you so muh for checking on this.
Answers
Answered by
lyne
CrO4 is a polyatomic ion so it is one big part
the charge on it is -2
the 4 has nothing to do with it
if it were (CrO4)4 then it would be unbalanced
the charge on it is -2
the 4 has nothing to do with it
if it were (CrO4)4 then it would be unbalanced
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