Asked by Sadia
Two cars are racing with a constant speed towards a finish Marker. Car a is moving from South at 16km/h and car But is moving from east. When equidistant from marker the cars are 18km apart and the distance between them is decreasing at the rate of 19km/h which car will win the race and explain your answer
Answers
Answered by
oobleck
when the distance z between the cars is 18 km, each is 18/√2 = 9√2 km from the marker.
Since z^2 = a^2+b^2,
z dz/dt = a da/dt + b db/dt
18(-19) = 9√2(-16) + 9√2 db/dt
b = 16-9√2 ≈ 10.87 km/hr
A will clearly get there first
Since z^2 = a^2+b^2,
z dz/dt = a da/dt + b db/dt
18(-19) = 9√2(-16) + 9√2 db/dt
b = 16-9√2 ≈ 10.87 km/hr
A will clearly get there first
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.