Asked by joe
Write the balanced molecular equation and net ionic equation for the neutralization reaction between hydrochloric acid and strontium hydroxide. Include the phase of each species.
Answers
Answered by
DrBob222
Sr(OH)2 is slightly soluble in water and the equations will be slightly different depending upon if the solid Sr(OH)2 or a solution of Sr(OH)2 is used. I'll write both.
First for the solid Sr(OH)2.
molecular equation:
2HCl(aq) + Sr(OH)2(s) ==> 2H2O(l) + SrCl2(aq)
Ionic equation:
2H^+(aq) + 2Cl^-(aq) + Sr(OH)2(s) ==> 2H2O(l) + Sr^2+(aq) + 2Cl^-(aq)
net ionic equation:
2H^+(aq) + Sr(OH)2(s) ==> 2H2O(l) + Sr^2+(aq)
Using solution of Sr(OH)2 and I suspect this is what your professor wants.
molecular equation:
2HCl(aq) + Sr(OH)2(aq) ==> 2H2O(l) + SrCl2(aq)
Ionic equation:
2H^+(aq) + 2Cl^-(aq) + Sr^2+(aq) + 2(OH)^-(aq) ==> 2H2O(l) + Sr^2+(aq) + 2Cl^-(aq)
Net ionic equation:
2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)
First for the solid Sr(OH)2.
molecular equation:
2HCl(aq) + Sr(OH)2(s) ==> 2H2O(l) + SrCl2(aq)
Ionic equation:
2H^+(aq) + 2Cl^-(aq) + Sr(OH)2(s) ==> 2H2O(l) + Sr^2+(aq) + 2Cl^-(aq)
net ionic equation:
2H^+(aq) + Sr(OH)2(s) ==> 2H2O(l) + Sr^2+(aq)
Using solution of Sr(OH)2 and I suspect this is what your professor wants.
molecular equation:
2HCl(aq) + Sr(OH)2(aq) ==> 2H2O(l) + SrCl2(aq)
Ionic equation:
2H^+(aq) + 2Cl^-(aq) + Sr^2+(aq) + 2(OH)^-(aq) ==> 2H2O(l) + Sr^2+(aq) + 2Cl^-(aq)
Net ionic equation:
2H^+(aq) + 2OH^-(aq) ==> 2H2O(l)
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