(14-4n) - (3n+4) = (4n-2) - (14+4n)
n = 26/7
so the common difference is (14-4n) - (3n+4) = -16
Show that each of the following sequences is an A.P and hence find the first 5 terms 3n+4,14n-4n, 4n-2
1 answer
1 answer
3 answers
1 answer
0 answers
1 answer