Asked by william
assume that f(x) is everywhere continuous and it is given to you that f(2)=-7 and
lim (f(x)+7)/(x-2)=8
x➟ 2
it follows that y = ?
I dont really understand how to solve this question as if you were to directly sub in x=2 then you get a zero on top which would leave the left side equal to 0/0=8? normally in other questions you would factor but with this you cant factor it.
thanks for any help
lim (f(x)+7)/(x-2)=8
x➟ 2
it follows that y = ?
I dont really understand how to solve this question as if you were to directly sub in x=2 then you get a zero on top which would leave the left side equal to 0/0=8? normally in other questions you would factor but with this you cant factor it.
thanks for any help
Answers
Answered by
oobleck
Given that the limit is 8, we really do need 0/0, otherwise the fraction goes to ∞. So y = -7. So, if f(2) is anything but -7, such as 3, then we have 10/0 which = ∞ -- but we are told that the limit is 8.
But they just told us that f(-2) = -7. So why ask what y is? Isn't y=f(x)?
But they just told us that f(-2) = -7. So why ask what y is? Isn't y=f(x)?
Answered by
william
assuming no miscommunication, this question is incredibly confusing. i think that what it might be asking is not the limit but what would make it equal to 8? so I would just plug in random numbers till I get the limit = 8
Answered by
oobleck
it is confusing. But since the limit is a finite value, the fraction must be 0/0. For, if 0/0 = n, then that means that 0 = n*0. But that is true for <b>any</b> finite n. So if they tell you that the limit is 8, the fraction <b>must</b> be 0/0, since the bottom is zero.
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