Give that log2=0.31 evaluate log16 without using table

Solve log2(7x-3)>= log2(x+12) My work: 6x=15 x=15/6 x-5/2 so my answer would be: x>= 5/2...

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Evaluate 6 log2 ∛64 +10log3 (243)^1/5)

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Evaluate. 1.log2 raise to the power of 4 2.log5 raise to the power of 25 3.log4 raise to the powe...

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Evaluate log2 32 =

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