Asked by ㅤㅤㅤㅤㅤ
Use the chemical reaction to answer the question.
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
(1 point)
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
(1 point)
Answers
Answered by
DrBob222
Law of conservation of mass.
mass CO2 + mass CaO = 30 g products = mass reactants = 30 g CaCO3.
mass CO2 + mass CaO = 30 g products = mass reactants = 30 g CaCO3.
Answered by
DrBob222
You can prove this by stoichiometry .
mols CaCO3 = grams/molar mass = 30/100 = 0.30
1 mole CaCO3 forms 1 mols CaO so 0.30 mols CaO.
grams CaO = moles CaO x molar mass CaO = 0.30 x 56 = 16.8 g
1 mol CaCO3 forms 1 mol CO2 = 0.30 mols CO2 formed.
grams CO2 = mols x molar mass = 0.30 x 44 = 13.2 g
total mass products = 16.8 + 13.2 = 30
mass reactants = 30 g = mass products
What goes in must come out.
mols CaCO3 = grams/molar mass = 30/100 = 0.30
1 mole CaCO3 forms 1 mols CaO so 0.30 mols CaO.
grams CaO = moles CaO x molar mass CaO = 0.30 x 56 = 16.8 g
1 mol CaCO3 forms 1 mol CO2 = 0.30 mols CO2 formed.
grams CO2 = mols x molar mass = 0.30 x 44 = 13.2 g
total mass products = 16.8 + 13.2 = 30
mass reactants = 30 g = mass products
What goes in must come out.
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