Asked by Anonymous
If we ignore air resistance, then the range R(š) of a baseball hit at an angle š with respect to the x axis and with initial velocity v0 is given by
R(š) = 1/g(v0)2 sin (2š) for 0 ⤠š < š/2
where g is the acceleration due to gravity.
(a) If v0 = 80 (meters per second) and g = 9.8 (meters per second per second), then
R ' (š/4)
R(š) = 1/g(v0)2 sin (2š) for 0 ⤠š < š/2
where g is the acceleration due to gravity.
(a) If v0 = 80 (meters per second) and g = 9.8 (meters per second per second), then
R ' (š/4)
Answers
Answered by
oobleck
a little more ligibly,
R = v^2/g sin2Īø
when you say R', derivative with respect to what?
Hmmm. it appears you mean dR/dĪø, with v constant.
dR/dĪø = 4v^2/g cos2Īø = 4*6400/9.81 * 1/ā2 = 1845.25 m/rad
R = v^2/g sin2Īø
when you say R', derivative with respect to what?
Hmmm. it appears you mean dR/dĪø, with v constant.
dR/dĪø = 4v^2/g cos2Īø = 4*6400/9.81 * 1/ā2 = 1845.25 m/rad
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