Asked by Abubakar
The third and ninthterm of a gp are 54 and 39366 respectively. Find the common ratio the first term sixth term and aum of the first ten terms
Answers
Answered by
oobleck
r^6 = 39366/54 = 729
r = ±3
a = 54/r^2 = 6
the 6th term is 54r^3 = ±1458
S10 = 6(r^10-1)/(r-1) = 177144 or -88572
r = ±3
a = 54/r^2 = 6
the 6th term is 54r^3 = ±1458
S10 = 6(r^10-1)/(r-1) = 177144 or -88572
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