Question
a ferryboat is travelling in a direction of 28 degrees north of east with a speed of 4.40 m/s relative to the water. A passenger is walking with a velocity of 2.20 m/s due east relative to the boat. What is the magnitude and direction of the velocity of the passenger with respect to the water. Give directional Angle to due east.
Answers
Anonymous
boat north rel to water = 4.4 sin 28
boat east rel to water = 4.4 cos 28
pass north rel to water = 4.4 sin 28 same as boat = 2.07
pass east rel to water = 4.4 cos 28 + 2.2 = 3.88 + 2.2 = 6.08
mag = sqrt (2.07^2 + 6.08^2)
tan angle N of E = 2.07/6.08
boat east rel to water = 4.4 cos 28
pass north rel to water = 4.4 sin 28 same as boat = 2.07
pass east rel to water = 4.4 cos 28 + 2.2 = 3.88 + 2.2 = 6.08
mag = sqrt (2.07^2 + 6.08^2)
tan angle N of E = 2.07/6.08