In a competition 3 points are awarded for every game won and 2 points are deducted for every game lost.A pupil attempted 5 games and got 5 points.How many games did he lose?

Answer 1

x = number of game won

y = number of game lost

A pupil attempted 5 games means:

x + y = 5

He got x ∙ 3 points for the games he won.

For lost games he lost y ∙ 2 points.

He got 5 points means:

x ∙ 3 - y ∙ 2 = 5

3 x - 2 y = 5

Now you must solve system of two equations;

x + y = 5

3 x - 2 y = 5

The solution is:

x = 3 , y = 2

He won 3 games

He lose 2 games

Check result.

x + y = 3 + 2 = 5

He attempted 5 games.

He got for winning the games x ∙ 3 = 3 ∙ 3 = 9 points

He lost for lost games 2 ∙ 2 points 2 = 4 points

9 points - 4 points = 5 points

Answer 2

3w-2(5-w)=5
3w-10+2w=5
5w_10=5
5w=15
W=3
Games won =3
Games lost=2

Answer 3

Correct! The pupil won 3 games and lost 2 games.