Asked by Prince animashaun dan
What is the mass of impurity in a sample of CaCo3, if 0.040 mole of Co2 was formed when 5.0g of the sample reacted with excess dilute hcl.
Answers
Answered by
DrBob222
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2
0.04 moles CO2 would come from 04 x 100 = 4.0 grams CaCO3
% purity = (4.0/5.0)*100 = 80%.
0.04 moles CO2 would come from 04 x 100 = 4.0 grams CaCO3
% purity = (4.0/5.0)*100 = 80%.
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