Asked by Anna
The bearing of Q from P is 150 and the bearing of P from R is 015 if Q and R are 24km and 32km respectively from P. represent this in a diagram calculate the distance Q and R to 2dp find the correct to the nearest degree
Answers
Answered by
oobleck
if you do the diagram, you can see that the law of cosines will produce the desired result. You just need to determine angle P in triangle PQR
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