Asked by Emmanuella
One quarter of the sum of two consecutive odd numbers is 14.Find the odd numbers
Answers
Answered by
Anonymous
n and n + 2
(1/4) (2 n+2) = 14
2 n + 2 = 56
2 n = 54
n = 27
==================
check
==================
(27+29) /4
56/4
14 sure enough
(1/4) (2 n+2) = 14
2 n + 2 = 56
2 n = 54
n = 27
==================
check
==================
(27+29) /4
56/4
14 sure enough
Answered by
Bosnian
Odd numbers have the general form:
n = 2 k - 1
where
k = real number (1, 2, 3...)
The first number is:
n1 = 2 k - 1
The difference between two consecutive odd numbers is 2, so the second number is:
n2 = n1 + 2 = 2 k - 1 + 2 = 2 k + 1
One quarter of the sum of two consecutive odd numbers is 14 means:
1 / 4 ( n1 + n2 ) = 14
Multiply both sides by 4.
n1 + n2 = 56
2 k - 1 + 2 k + 1 = 56
4 k = 56
k = 56 / 4
k = 14
The first odd number is:
n1 = 2 k - 1
n1 = 2 • 14 - 1 = 28 - 1 = 27
The second odd number is:
n2 = 2 k + 1
n2 = 2 • 14 + 1 = 28 + 1 = 29
So two consecutive odd numbers are 27 and 29.
Check the result.
( 27 + 29 ) / 4 = 56 / 4 = 14
n = 2 k - 1
where
k = real number (1, 2, 3...)
The first number is:
n1 = 2 k - 1
The difference between two consecutive odd numbers is 2, so the second number is:
n2 = n1 + 2 = 2 k - 1 + 2 = 2 k + 1
One quarter of the sum of two consecutive odd numbers is 14 means:
1 / 4 ( n1 + n2 ) = 14
Multiply both sides by 4.
n1 + n2 = 56
2 k - 1 + 2 k + 1 = 56
4 k = 56
k = 56 / 4
k = 14
The first odd number is:
n1 = 2 k - 1
n1 = 2 • 14 - 1 = 28 - 1 = 27
The second odd number is:
n2 = 2 k + 1
n2 = 2 • 14 + 1 = 28 + 1 = 29
So two consecutive odd numbers are 27 and 29.
Check the result.
( 27 + 29 ) / 4 = 56 / 4 = 14
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