Asked by Anonymous
Could you please help me with this thanks.
6a(-5 power)b(2nd power)c(-3 power)
6a(-5 power)b(2nd power)c(-3 power)
Answers
Answered by
Bob
Are you solving for anything? You can rewrite that as:
b^2/[(6a^5)(c^3)]
b^2/[(6a^5)(c^3)]
Answered by
Anonymous
No it just says simplify
Answered by
Bob
Then that should be your answer
Answered by
Anonymous
Thanks for your help could you help me with this you use the equation a^2* b^2= c^2.
You have to find x so would x be a, b, or c I'm not sure cause it doesn't say on my paper.
You have to find x so would x be a, b, or c I'm not sure cause it doesn't say on my paper.
Answered by
Anonymous
I mean you have to find the x length so here are the numbers 25, and 7. So I did 25^2+7^2=c^2
Then I put 625+49= 674
Did I do this right??
Then I put 625+49= 674
Did I do this right??
Answered by
Bob
That is the Pythagorean theorem, which states that:
in any right triangle, the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares whose sides are the two legs.
in any right triangle, the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares whose sides are the two legs.
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