Asked by Paul
New York City’s 7.9 million people in 1978 had a daily per capita consumption of 676
liters of water. How many metric tons (103 kg) of sodium fluoride (45% fluorine by
weight) would be required per year to give this water a tooth-strengthening dose of 1
part (by weight) fluorine per million parts water? The density of water is 1.000 g/cm3, or
1.000 kg/L.
liters of water. How many metric tons (103 kg) of sodium fluoride (45% fluorine by
weight) would be required per year to give this water a tooth-strengthening dose of 1
part (by weight) fluorine per million parts water? The density of water is 1.000 g/cm3, or
1.000 kg/L.
Answers
Answered by
DrBob222
How many liters.
7.9E6 people x 676 L/person/yr = 5.340E9 L
1 ppm = 1 mg F^-/L = 1 mg x (1/0.45)/L so for 5.34E9L you will need
1 mg x 1/0.45 x 5.34E9 L = total mg
Convert total mg to metric tons (10^3 kg) you will need of NaF.
7.9E6 people x 676 L/person/yr = 5.340E9 L
1 ppm = 1 mg F^-/L = 1 mg x (1/0.45)/L so for 5.34E9L you will need
1 mg x 1/0.45 x 5.34E9 L = total mg
Convert total mg to metric tons (10^3 kg) you will need of NaF.
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