Question
when 435J of heat is added to 3.40grams of olive oil at 21c the temperature increases 85.0c
Answers
I don't see a question but I assum you want to solve for the specific heat of the olive oil.
q = mc*deltaT
435 = 3.40 g * specific heat x 85 C
Solve for specific heat in J/g*C
Post your work if you get stuck.
q = mc*deltaT
435 = 3.40 g * specific heat x 85 C
Solve for specific heat in J/g*C
Post your work if you get stuck.
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