Question

The first three terms of a GP are (K-3)(2K-4)(4K-3) in that order find value of K and the sum of the first 8 terms.

Answer 1

I don't know nay answer

Answer 2

(k-3)(4k-3) = (2k-4)^2
k = 7
That makes
a = 4
r = 5/2
S8 = a(r^8-1)/(r-1)