Asked by Anonymous
If you had excess chlorine, how many moles of of aluminum chloride could be produced from 34.0 g of aluminum?
Answers
Answered by
oobleck
2Al + 3Cl2 → 2AlCl3
how many moles of Al in 34.0 g?
you will get that many moles of AlCl3
how many grams is that?
how many moles of Al in 34.0 g?
you will get that many moles of AlCl3
how many grams is that?
Answered by
DrBob222
2Al + 3Cl2 --> 2AlCl3
mols Al = grams/atomic mass = 34.0/27 = 1.26
Convert to mols AlCl3 produced using the coefficients in the balanced equation this way: 1.26 mols Al x (2 mols AlCl3/2 moles Al) = 1.26 x 2/2 = 1.26.
mols Al = grams/atomic mass = 34.0/27 = 1.26
Convert to mols AlCl3 produced using the coefficients in the balanced equation this way: 1.26 mols Al x (2 mols AlCl3/2 moles Al) = 1.26 x 2/2 = 1.26.
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