Asked by Anonymous
lim x->-∞ arctan( |9- 4x^2| / 3 - 4x^2 - 4x )
Answers
Answered by
Bosnian
This is difficult to explain, so it is best to use an online service.
In google paste:
limit calculator emathhelp
When you see list of results click on:
Limit Calculator - eMathHelp
When page be open in rectangle
Enter a function
paste:
atan ( abs (9- 4x^2) /( 3 - 4x^2 - 4x) )
In rectangle Find the limit at
type
inf
then click option
CALCULATE
You will see solution step by step.
I'll give you an explanation of the last step in the calculation because it can be confusing the way it's written.
( 4 ( - 4 + 3 ( 0 ) )⁻¹ ) =
4 • ( - 4 + 3 • 0 )⁻¹ =
4 • ( - 4 + 0 )⁻¹ = 4 • ( - 4 )⁻¹
__________________________________
Remark:
a⁻ⁿ = 1 / aⁿ
so
( - 4 )⁻¹ = 1 / - 4¹ = 1 / - 4 = - 1 / 4
__________________________________
4 • ( - 4 )⁻¹ = 4 • ( - 1 ) / 4 = - 1
atan ( 4 ( - 4 + 3 ( 0 ) ) ⁻¹ ) =
atan ( - 1 ) = - π / 4
In google paste:
limit calculator emathhelp
When you see list of results click on:
Limit Calculator - eMathHelp
When page be open in rectangle
Enter a function
paste:
atan ( abs (9- 4x^2) /( 3 - 4x^2 - 4x) )
In rectangle Find the limit at
type
inf
then click option
CALCULATE
You will see solution step by step.
I'll give you an explanation of the last step in the calculation because it can be confusing the way it's written.
( 4 ( - 4 + 3 ( 0 ) )⁻¹ ) =
4 • ( - 4 + 3 • 0 )⁻¹ =
4 • ( - 4 + 0 )⁻¹ = 4 • ( - 4 )⁻¹
__________________________________
Remark:
a⁻ⁿ = 1 / aⁿ
so
( - 4 )⁻¹ = 1 / - 4¹ = 1 / - 4 = - 1 / 4
__________________________________
4 • ( - 4 )⁻¹ = 4 • ( - 1 ) / 4 = - 1
atan ( 4 ( - 4 + 3 ( 0 ) ) ⁻¹ ) =
atan ( - 1 ) = - π / 4
Answered by
oobleck
3 - 4x^2 - 4x = -(4x^2+4x-3) = -(2x-1)(2x+3)
so now we have
|(2x+3)(2x-3)|/(-(2x+3)(2x-1)) = -|2x-3|/(2x-1)
lim(x→-∞) = -1
and arctan(-1) = -π/4
so now we have
|(2x+3)(2x-3)|/(-(2x+3)(2x-1)) = -|2x-3|/(2x-1)
lim(x→-∞) = -1
and arctan(-1) = -π/4
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