Asked by Khara
20,17,13,8,2,-5 whats the term to term rule
Answers
Answered by
Bosnian
This can only be solved using an interpolating polynomial.
Terms are:
20 , 17 ,13 , 8 , 2 , - 5
17 - 20 = - 3
13 - 17 = - 4
8 - 13 = - 5
2 - 8 = - 6
- 5 - 2 = - 7
The first order differences are:
- 3 , - 4 , - 5 , - 6 , - 7
__________________
- 4 - ( - 3 ) = - 4 + 3 = - 1
- 5 - ( - 4 ) = - 5 + 4 = - 1
- 6 - ( - 5 ) = - 6 + 5 = - 1
- 7 - ( - 6 ) = - 7 + 6 = - 1
Differences of the second order are constant, so the interpolating polynomial is the second degree.
A polynomial of the second degree requires 2 + 1 = 3 points.
Let the points be:
n = 1 , t1 = 20
n = 2 , t2 = 17
n = 3 , t3 = 13
Interpolating polynomial:
tn = a n² + b • n + c
n = 1 , tn = t1
t1= a • 1² + b • 1 + c = 20
a + b + c = 20
n = 2 , tn = t2
t2= a • 2² + b • 2 + c = 17
4 a + 2 b + c = 17
n = 3 , tn = t3
t3= a • 3² + b • 3 + c = 13
9 a + 3 b + c = 13
Now solve system of 3 equations:
a + b + c = 20
4 a + 2 b + c = 17
9 a + 3 b + c = 13
The solution is:
a = - 1 / 2 , b = - 3 / 2 , c = 22
Interpolating polynomial:
tn = a n² + b • n + c
tn = - 1 / 2 n² - 3 / 2 • n + 22
tn = - 1 / 2 ( n² + 3 n - 44 )
Terms are:
20 , 17 ,13 , 8 , 2 , - 5
17 - 20 = - 3
13 - 17 = - 4
8 - 13 = - 5
2 - 8 = - 6
- 5 - 2 = - 7
The first order differences are:
- 3 , - 4 , - 5 , - 6 , - 7
__________________
- 4 - ( - 3 ) = - 4 + 3 = - 1
- 5 - ( - 4 ) = - 5 + 4 = - 1
- 6 - ( - 5 ) = - 6 + 5 = - 1
- 7 - ( - 6 ) = - 7 + 6 = - 1
Differences of the second order are constant, so the interpolating polynomial is the second degree.
A polynomial of the second degree requires 2 + 1 = 3 points.
Let the points be:
n = 1 , t1 = 20
n = 2 , t2 = 17
n = 3 , t3 = 13
Interpolating polynomial:
tn = a n² + b • n + c
n = 1 , tn = t1
t1= a • 1² + b • 1 + c = 20
a + b + c = 20
n = 2 , tn = t2
t2= a • 2² + b • 2 + c = 17
4 a + 2 b + c = 17
n = 3 , tn = t3
t3= a • 3² + b • 3 + c = 13
9 a + 3 b + c = 13
Now solve system of 3 equations:
a + b + c = 20
4 a + 2 b + c = 17
9 a + 3 b + c = 13
The solution is:
a = - 1 / 2 , b = - 3 / 2 , c = 22
Interpolating polynomial:
tn = a n² + b • n + c
tn = - 1 / 2 n² - 3 / 2 • n + 22
tn = - 1 / 2 ( n² + 3 n - 44 )
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