Asked by Anna
(1) log(4+x) base 8 + log y base 8 = 2 log(x+52) base 4 - log y base 4= 2
(2) if log (p+q) base 3 =1 and log (2p-q) base 2 = 2 find the value of pq
(2) if log (p+q) base 3 =1 and log (2p-q) base 2 = 2 find the value of pq
Answers
Answered by
oobleck
(1).
(x+4)y = 64
(x+2)^2/y = 16
now multiply to get
(x+4)(x+2)^2 = 1024
hmmm. not rational. better check my math.
(2).
p+q = 3
2p-q = 4
add to get
3p = 7
...
(x+4)y = 64
(x+2)^2/y = 16
now multiply to get
(x+4)(x+2)^2 = 1024
hmmm. not rational. better check my math.
(2).
p+q = 3
2p-q = 4
add to get
3p = 7
...
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