1 answer
(click or scroll down)
V air after = 35/40 V original of air
so p air = 40/35 atm
40 - 35 = 5 cm of Hg in tube
5 cm hg = 5/77 atm of hg pressure
so total pressure at bottom of inside of tube = 40/35 atm + 5/77 atm
= 1.14 + 0.065 atm = 1.205 atm
outside the tube at the bottom
p = 1 atm + rho g h water
so
.205 atm = rho g * h
0.205 atm* 101325 N/m^2 / atm = 20772 pascals or N/m^2
so
20772 N/m^2 = 1000 Kg/m^3 * 9.81 m/s^2 * h
h = 0.126 meters
12.6 cm