Asked by Michaela
consider this reaction : 2SO2 + O2 =2SO3 if 96g SO2 is added to 2 moles of oxygen at STP calculate the volume of oxygen used
Answers
Answered by
DrBob222
2SO2 + O2 =2SO3
moles SO2 = g/molar mass = 96/64 = 1.5
moles O2 used = 1.5 mols SO2 x (1 mol O2/2 mols SO2) = 0.75
1 mol SO2 @ STP will occupy 22.4 L so 0.75 mol will occupy 22.4 x 0.75 = ?
moles SO2 = g/molar mass = 96/64 = 1.5
moles O2 used = 1.5 mols SO2 x (1 mol O2/2 mols SO2) = 0.75
1 mol SO2 @ STP will occupy 22.4 L so 0.75 mol will occupy 22.4 x 0.75 = ?