Asked by yuj
What is the locus of the centers of circles touching the line
8𝑥 − 𝑦 − 3 = 0 at (1,5)?
8𝑥 − 𝑦 − 3 = 0 at (1,5)?
Answers
Answered by
denz
What are the equations of the lines perpendicular to the line
3𝑥 − 𝑦 + 6 = 0 and passing at a distance ±3 from the origin?
3𝑥 − 𝑦 + 6 = 0 and passing at a distance ±3 from the origin?
Answered by
oobleck
it is the line through (1,5) perpendicular to 8x-y-3=0
That is, the line
y-5 = -1/8 (x-1)
Those would be lines with slope -1/3 tangent to the circle x^2+y^2 = 9
see what you can do with that.
That is, the line
y-5 = -1/8 (x-1)
Those would be lines with slope -1/3 tangent to the circle x^2+y^2 = 9
see what you can do with that.
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