Asked by joseph
5x-2 is factor of x3-3x2+kx+15
Answers
Answered by
Bosnian
Since 5 x - 2 is a facto.
For
5 x - 2 = 0
x³ - 3 x² + k x + 15 is also equlal zero
5 x - 2 = 0
Add 2 to both sides
5 x = 2
x = 2 / 5
so
f(2/5) = 0
f(2/5) =
( 2 / 5 )³ - 3 ( 2 / 5 )² + k • 2 / 5 + 15 = 0
When you calculate this it will be:
1823 / 125 + 2 k / 5 = 0
Subtract 1823 / 125 to both suded.
2 k / 5 = - 1823 / 125
Multiply both sides by 5
2 k = - 5 • 1823 / 125
2 k = - 5 • 1823 / 5 • 25
2 k = - 1823 / 25
Divide both sides by 2
k = - 1823 / 50
For
5 x - 2 = 0
x³ - 3 x² + k x + 15 is also equlal zero
5 x - 2 = 0
Add 2 to both sides
5 x = 2
x = 2 / 5
so
f(2/5) = 0
f(2/5) =
( 2 / 5 )³ - 3 ( 2 / 5 )² + k • 2 / 5 + 15 = 0
When you calculate this it will be:
1823 / 125 + 2 k / 5 = 0
Subtract 1823 / 125 to both suded.
2 k / 5 = - 1823 / 125
Multiply both sides by 5
2 k = - 5 • 1823 / 125
2 k = - 5 • 1823 / 5 • 25
2 k = - 1823 / 25
Divide both sides by 2
k = - 1823 / 50
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