Asked by Maki

If log2 base7 is 0.3562,log3 base7 is 0.5646 and log 5 base 7 is 0.8271 evaluate log30 base7

Answers

Answered by Maki
1.7479
Answered by Bosnian
This rule applies to logarithms with any base.

log ( a • b ) = log ( a ) + log ( b )

so

log ( a • b • c ) =

log ( a ) + log ( b ) + log ( c )

30 = 2 • 3 • 5

log₇ ( 30 ) = log ₇ ( 2 • 3 • 5 ) =

log₇ ( 2 ) + log₇ ( 3 ) + log₇ ( 5 ) =

0.3562 + 0.5646 + 0.8271 = 1.7479


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