Asked by Nimusiima
A solid weighs 20n in air and 12n in water determine the density of the solid
Answers
Answered by
Anonymous
water weight displaced = 20 - 12 = 8 N
water mass displaced = 8 / 9.81 = 0.815 kg
water volume displaced =0.815 kg * ( 1 meter^3/1000 kg) = 0.000815 m^3
= volume of the solid
mass of solid = 20 /9.81 = 2.04 kg
so
density = mass/volume = 2.04 / .000815 = 2502 kg / m^3
or about 2.5 times the density of water
water mass displaced = 8 / 9.81 = 0.815 kg
water volume displaced =0.815 kg * ( 1 meter^3/1000 kg) = 0.000815 m^3
= volume of the solid
mass of solid = 20 /9.81 = 2.04 kg
so
density = mass/volume = 2.04 / .000815 = 2502 kg / m^3
or about 2.5 times the density of water
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