Asked by Ogun
The 10th term of an AP is 68 and the d is 7 find the first term of the sequence
Answers
Answered by
Bosnian
In AP:
an = a1 + ( n - 1 ) d
a10 = a1 + 9 d
68 = a1 + 9 • 7
68 = a1 + 63
Subtract 63 to both sides.
5 = a1
a1 = 5
an = a1 + ( n - 1 ) d
a10 = a1 + 9 d
68 = a1 + 9 • 7
68 = a1 + 63
Subtract 63 to both sides.
5 = a1
a1 = 5
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