Asked by Anonymous
There were 80 adults at a fund-raising event. Each adult collected an average of 5534. The average amount of money collected by the men was $633 and the average amount of money collected by the women was $453. How many women were there at the fund-raising event?
Answers
Answered by
Anonymous
let the number of men be x
let the number of women be y
=> x + y = 80 - (1)
Total number of money collected
= 534(x + y) = 534x + 534y
Total amount collected by men
= 633x
Total amount collected by women
= 534x + 534y - 633x
= 534y - 99x
Amount collected by women
= 453y
453y = 534y - 99x
=> 99x = 81y
=> x = 81/99y = 9/11y
9/11y for x in (1)
=> 9/11y + y = 80
=> 20y = 80 * 11
=> y = (80 * 11)/20 = 44
There were 44 women at the event.
let the number of women be y
=> x + y = 80 - (1)
Total number of money collected
= 534(x + y) = 534x + 534y
Total amount collected by men
= 633x
Total amount collected by women
= 534x + 534y - 633x
= 534y - 99x
Amount collected by women
= 453y
453y = 534y - 99x
=> 99x = 81y
=> x = 81/99y = 9/11y
9/11y for x in (1)
=> 9/11y + y = 80
=> 20y = 80 * 11
=> y = (80 * 11)/20 = 44
There were 44 women at the event.
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