Asked by Abdulah
Solve for the constants a and b that make the piecewise function continuous
f(x) = 2x-A-B, x≥3
Ax^2-Bx+3, 2≤x<3
x^2-4/x-2, x<2
f(x) = 2x-A-B, x≥3
Ax^2-Bx+3, 2≤x<3
x^2-4/x-2, x<2
Answers
Answered by
oobleck
for x < 2, f(x) = x+2 so f(2) = 4
Now you need
4A-2b+3 = 4
f(3) = 9A-3b+3
so you need
2*3-A-B = 9A-3b+3
Now finish it off
Now you need
4A-2b+3 = 4
f(3) = 9A-3b+3
so you need
2*3-A-B = 9A-3b+3
Now finish it off
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